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如何使用vba解析XML

如何解决《如何使用vba解析XML》经验,为你挑选了5个好方法。

我在VBA工作,想要解析一个字符串,例如


    24.365
    78.63

并将X和Y值分成两个独立的整数变量.

在XML方面我是新手,因为我在VB6和VBA中工作,因为我工作的领域.

我该怎么做呢?



1> Devdatta Ten..:

谢谢你的指点.

我不知道,这是否是解决问题的最佳方法,但这就是我如何让它发挥作用.我在我的VBA中引用了Microsoft XML,v2.6 dll,然后是以下代码片段,它为我提供了所需的值

Dim objXML As MSXML2.DOMDocument

    Set objXML = New MSXML2.DOMDocument

    If Not objXML.loadXML(strXML) Then  'strXML is the string with XML'
        Err.Raise objXML.parseError.ErrorCode, , objXML.parseError.reason
    End If

Dim point As IXMLDOMNode
Set point = objXML.firstChild

Debug.Print point.selectSingleNode("X").Text
Debug.Print point.selectSingleNode("Y").Text



2> rjzii..:

这是一个复杂的问题,但似乎最直接的方法是通过MSXML2.DOMDocument加载XML文档或XML字符串,然后允许您访问XML节点.

您可以在以下站点上找到有关MSXML2.DOMDocument的更多信息:

使用Excel VBA和Xpath操作XML文件

MSXML - http://msdn.microsoft.com/en-us/library/ms763742(VS.85).aspx

MSXML 4.0概述



3> mvanle..:

您可以使用XPath查询:

Dim objDom As Object        '// DOMDocument
Dim xmlStr As String, _
    xPath As String

xmlStr = _
    " " & _
    "    24.365 " & _
    "    78.63 " & _
    ""

Set objDom = CreateObject("Msxml2.DOMDocument.3.0")     '// Using MSXML 3.0

'/* Load XML */
objDom.LoadXML xmlStr

'/*
' * XPath Query
' */        

'/* Get X */
xPath = "/PointN/X"
Debug.Print objDom.SelectSingleNode(xPath).text

'/* Get Y */
xPath = "/PointN/Y"
Debug.Print objDom.SelectSingleNode(xPath).text



4> No Name..:

添加引用Project-> References Microsoft XML,6.0,您可以使用示例代码:

    Dim xml As String

    xml = "Me    No Name  "
    Dim oXml As MSXML2.DOMDocument60
    Set oXml = New MSXML2.DOMDocument60
    oXml.loadXML xml
    Dim oSeqNodes, oSeqNode As IXMLDOMNode

    Set oSeqNodes = oXml.selectNodes("//root/person")
    If oSeqNodes.length = 0 Then
       'show some message
    Else
        For Each oSeqNode In oSeqNodes
             Debug.Print oSeqNode.selectSingleNode("name").Text
        Next
    End If 

小心xml节点// Root/Person与// root/person不一样,selectSeingleNode("Name").text与selectSingleNode("name")不一样.


一些问题:为什么路径是// root,而不是/ root?如果我的oSeqNode中只有一个人,如何在“仅那个人”中子选择所有<telephone>?

5> 小智..:

这是使用FeedDemon opml文件的示例OPML解析器:

Sub debugPrintOPML()

' http://msdn.microsoft.com/en-us/library/ms763720(v=VS.85).aspx
' http://msdn.microsoft.com/en-us/library/system.xml.xmlnode.selectnodes.aspx
' http://msdn.microsoft.com/en-us/library/ms256086(v=VS.85).aspx ' expressions
' References: Microsoft XML

Dim xmldoc As New DOMDocument60
Dim oNodeList As IXMLDOMSelection
Dim oNodeList2 As IXMLDOMSelection
Dim curNode As IXMLDOMNode
Dim n As Long, n2 As Long, x As Long

Dim strXPathQuery As String
Dim attrLength As Byte
Dim FilePath As String

FilePath = "rss.opml"

xmldoc.Load CurrentProject.Path & "\" & FilePath

strXPathQuery = "opml/body/outline"
Set oNodeList = xmldoc.selectNodes(strXPathQuery)

For n = 0 To (oNodeList.length - 1)
    Set curNode = oNodeList.Item(n)
    attrLength = curNode.Attributes.length
    If attrLength > 1 Then ' or 2 or 3
        Call processNode(curNode)
    Else
        Call processNode(curNode)
        strXPathQuery = "opml/body/outline[position() = " & n + 1 & "]/outline"
        Set oNodeList2 = xmldoc.selectNodes(strXPathQuery)
        For n2 = 0 To (oNodeList2.length - 1)
            Set curNode = oNodeList2.Item(n2)
            Call processNode(curNode)
        Next
    End If
        Debug.Print "----------------------"
Next

Set xmldoc = Nothing

End Sub

Sub processNode(curNode As IXMLDOMNode)

Dim sAttrName As String
Dim sAttrValue As String
Dim attrLength As Byte
Dim x As Long

attrLength = curNode.Attributes.length

For x = 0 To (attrLength - 1)
    sAttrName = curNode.Attributes.Item(x).nodeName
    sAttrValue = curNode.Attributes.Item(x).nodeValue
    Debug.Print sAttrName & " = " & sAttrValue
Next
    Debug.Print "-----------"

End Sub

这个文件夹的多层树(Awasu,NewzCrawler):

...
Call xmldocOpen4
Call debugPrintOPML4(Null)
...

Dim sText4 As String

Sub debugPrintOPML4(strXPathQuery As Variant)

Dim xmldoc4 As New DOMDocument60
'Dim xmldoc4 As New MSXML2.DOMDocument60 ' ?
Dim oNodeList As IXMLDOMSelection
Dim curNode As IXMLDOMNode
Dim n4 As Long

If IsNull(strXPathQuery) Then strXPathQuery = "opml/body/outline"

' http://msdn.microsoft.com/en-us/library/ms754585(v=VS.85).aspx
xmldoc4.async = False
xmldoc4.loadXML sText4
If (xmldoc4.parseError.errorCode <> 0) Then
   Dim myErr
   Set myErr = xmldoc4.parseError
   MsgBox ("You have error " & myErr.reason)
Else
'   MsgBox xmldoc4.xml
End If

Set oNodeList = xmldoc4.selectNodes(strXPathQuery)

For n4 = 0 To (oNodeList.length - 1)
    Set curNode = oNodeList.Item(n4)
    Call processNode4(strXPathQuery, curNode, n4)
Next

Set xmldoc4 = Nothing

End Sub

Sub processNode4(strXPathQuery As Variant, curNode As IXMLDOMNode, n4 As Long)

Dim sAttrName As String
Dim sAttrValue As String
Dim x As Long

For x = 0 To (curNode.Attributes.length - 1)
    sAttrName = curNode.Attributes.Item(x).nodeName
    sAttrValue = curNode.Attributes.Item(x).nodeValue
    'If sAttrName = "text"
    Debug.Print strXPathQuery & " :: " & sAttrName & " = " & sAttrValue
    'End If
Next
    Debug.Print ""

If curNode.childNodes.length > 0 Then
    Call debugPrintOPML4(strXPathQuery & "[position() = " & n4 + 1 & "]/" & curNode.nodeName)
End If

End Sub

Sub xmldocOpen4()

Dim oFSO As New FileSystemObject ' Microsoft Scripting Runtime Reference
Dim oFS
Dim FilePath As String

FilePath = "rss_awasu.opml"
Set oFS = oFSO.OpenTextFile(CurrentProject.Path & "\" & FilePath)
sText4 = oFS.ReadAll
oFS.Close

End Sub

或更好:

Sub xmldocOpen4()

Dim FilePath As String

FilePath = "rss.opml"

' function ConvertUTF8File(sUTF8File):
' http://www.vbmonster.com/Uwe/Forum.aspx/vb/24947/How-to-read-UTF-8-chars-using-VBA
' loading and conversion from Utf-8 to UTF
sText8 = ConvertUTF8File(CurrentProject.Path & "\" & FilePath)

End Sub

但我不明白,为什么每次都应该加载xmldoc4.

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