如何在以下代码中将参数传递给函数指针？

如果你typedef的函数指针,这种调用更容易理解:

#include
#include

// addFuncPtr_t is a pointer to a function that:
// - returns int
// - takes two int arguments
typedef int ( *addFuncPtr_t )( int, int );

int add(int x, int y) {
    return (x + y);
}
void passptr(addFuncPtr_t fp, int a, int b) {
    int result = fp(a, b);
    printf("%d", result);
}
int main() {
    add(3, 5);

    // note that the function is passed separately from
    // the arguments - add(3,5) would *call* the function
    // instead of passing the address of the function
    passptr( add, 3, 5 );
    getch();
    return 0;
}