我正在尝试创建一个简单的天气应用程序来抓取用户的位置,并使用Google Maps api显示简单的天气数据.一切正常,除了这部分我拿JSON并获取地址.
func getAddressForLatLng(latitude: String, longitude: String) { let url = NSURL(string: "\(baseUrl)latlng=\(latitude),\(longitude)&key=\(apikey)") let data = NSData(contentsOf: url! as URL) let json = try! JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.allowFragments) as! Dictionary if let result = json["results"] as? Dictionary { if let address = result[0]["address_components"] as? Array { let number = address[0]["short_name"] as! String let street = address[1]["short_name"] as! String let city = address[2]["short_name"] as! String let state = address[4]["short_name"] as! String let zip = address[6]["short_name"] as! String weatherDisplay.text = "\(city),\(state)" } } }
在线上:
let json = try! JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.allowFragments) as! Dictionary
我收到此错误:
Cannot invoke 'jsonObject' with an argument list of type '(with: NSData?, options: JSONSerialization.ReadingOptions)'
我究竟做错了什么?
let nsdata = NSData() let data = Data(referencing: nsdata)
https://developer.apple.com/documentation/foundation/data/2224197-init
您需要更改几件事。首先,您正在使用NSData
。您应该使用Swift类型Data
。要从转换NSData?
为Data?
,只需将其添加as Data?
到变量声明的末尾。
另外,您的类型是可选的,但是您不能传递可选的类型,因此您需要解开它(在此示例中,使用if let data = data { /* stuff here */}
):
func getAddressForLatLng(latitude: String, longitude: String) { let url = NSURL(string: "\(baseUrl)latlng=\(latitude),\(longitude)&key=\(apikey)") let data = NSData(contentsOf: url! as URL) as Data? // <==== Added 'as Data?' if let data = data { // <====== Added 'if let' let json = try! JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.allowFragments) as! Dictionary if let result = json["results"] as? Dictionary { if let address = result[0]["address_components"] as? Array { let number = address[0]["short_name"] as! String let street = address[1]["short_name"] as! String let city = address[2]["short_name"] as! String let state = address[4]["short_name"] as! String let zip = address[6]["short_name"] as! String weatherDisplay.text = "\(city),\(state)" } } } }
更新:
您需要更改的另一件事是:
let json = try! JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.allowFragments) as! Dictionary
转换为类型时Dictionary
,编译器不知道您在说什么,因为Dictionary
它是泛型类型。因此,您需要强制转换为Dictionary
或[String: AnyObject]
(它们相同)。