SQL日期范围拆分

这应该是诀窍(MySQL方言,但很容易适应)

初始设置

SQL query: SELECT * FROM `test` LIMIT 0, 30 ;
Rows: 3
start       end
2008-01-01  2010-12-31
2009-01-01  2012-12-31
2009-01-01  2014-12-31

询问

SELECT 
  `start` , min( `end` )
FROM (
  SELECT t1.start, t2.end
  FROM test t1, test t2
  WHERE t1.start < t2.end
  UNION
  SELECT t1.end + INTERVAL 1 DAY , t2.end
  FROM test t1, test t2
  WHERE t1.end + INTERVAL 1 DAY < t2.end
  UNION
  SELECT t1.start, t2.start - INTERVAL 1 DAY
  FROM test t1, test t2
  WHERE t1.start < t2.start - INTERVAL 1 DAY
) allRanges
GROUP BY `start`

结果

start       min( `end` )
2008-01-01  2008-12-31
2009-01-01  2010-12-31
2011-01-01  2012-12-31
2013-01-01  2014-12-31