使用浏览器转换XML时,是否可以通过URL将参数传递给XSLT？

JavaScript函数如下:

//Get querystring request paramter in javascript
function getParameter (parameterName ) {

   var queryString = window.top.location.search.substring(1);

   // Add "=" to the parameter name (i.e. parameterName=value)
   var parameterName = parameterName + "=";
   if ( queryString.length > 0 ) {
      // Find the beginning of the string
      begin = queryString.indexOf ( parameterName );
      // If the parameter name is not found, skip it, otherwise return the value
      if ( begin != -1 ) {
         // Add the length (integer) to the beginning
         begin += parameterName.length;
         // Multiple parameters are separated by the "&" sign
         end = queryString.indexOf ( "&" , begin );
      if ( end == -1 ) {
         end = queryString.length
      }
      // Return the string
      return unescape ( queryString.substring ( begin, end ) );
   }
   // Return "null" if no parameter has been found
   return "null";
   }
}