使用Apache Commons Exec时,如何单独收集标准输出和标准错误？

下面的代码获取所有输出,无论是stdout还是stderr.

String line = String.format("paty/to/script.py");
CommandLine cmd = CommandLine.parse(line);
DefaultExecutor executor = new DefaultExecutor();
ByteArrayOutputStream stdout = new ByteArrayOutputStream();
PumpStreamHandler psh = new PumpStreamHandler(stdout);
executor.setStreamHandler(psh);
int exitvalue = executor.execute(cmd);
String output = stdout.toString();

如何单独获取两个流？

PumpStreamHandler为stderr获取第二个构造函数参数.OutputStream正如您所观察到的那样,只有一个构造函数会将stdout和stderr写入其中.
请参阅 https://commons.apache.org/proper/commons-exec/apidocs/org/apache/commons/exec/PumpStreamHandler.html

所以下面的方法应该处理它.

    String line = String.format("paty/to/script.py");
    CommandLine cmd = CommandLine.parse(line);
    DefaultExecutor executor = new DefaultExecutor();
    ByteArrayOutputStream stdout = new ByteArrayOutputStream();
    ByteArrayOutputStream stderr = new ByteArrayOutputStream();
    PumpStreamHandler psh = new PumpStreamHandler(stdout, stderr);
    executor.setStreamHandler(psh);
    int exitvalue = executor.execute(cmd);
    String output = stdout.toString();
    String error = stderr.toString();