所以我正在尝试为我正在构建的OpenLayers 3应用程序创建打印映射函数.我知道他们的例子,但每当我尝试使用它时,我都遇到了可怕的污点画布问题.我已经阅读了整个互联网并且遇到了人们首先正确设置CORS(完成和完成)但也要做:
var img = new Image(); img.setAttribute('crossOrigin', 'anonymous'); img.src = url;
以上描述了在这里.
我的问题是,我以前从未真正使用过toDataURL(),而且我不确定如何确保正在创建的图像在被激活之前正确设置了crossOrigin属性:
Error: Failed to execute 'toDataURL' on 'HTMLCanvasElement': Tainted canvases may not be exported.
有什么想法吗?
我见过这个.我的问题是他们如何将其纳入一个有效的功能.就像是:
var printMap = function(){ var img = new Image(); img.setAttribute('crossOrigin', 'anonymous'); img.src = url; img.onload = function() { var canvas = document.getElementsByTagName('canvas'); var dataURL = canvas.toDataURL("image/png"); console.log(dataURL); }; };
Kaiido.. 7
如果crossOrigin
浏览器支持属性/属性(现在它在FF,Chrome,最新的Safari和Edge中),但是服务器没有使用正确的标题(Access-Control-Allow-Origin: *
)回答,那么img的onerror
事件就会触发.
因此,如果我们想要绘制图像,我们可以只处理此事件并删除属性.
对于不处理此属性的浏览器,测试画布是否被污染的唯一方法是调用toDataURL
try catch块.
这是一个例子:
var urls =
["http://upload.wikimedia.org/wikipedia/commons/4/47/PNG_transparency_demonstration_1.png",
"http://lorempixel.com/200/200"];
var tainted = false;
var img = new Image();
img.crossOrigin = 'anonymous';
var canvas = document.createElement('canvas');
var ctx = canvas.getContext('2d');
document.body.appendChild(canvas);
var load_handler = function() {
canvas.width = 200;
canvas.height = 200;
ctx.fillStyle = 'white';
ctx.font = '15px sans-serif';
ctx.drawImage(this, 0, 0, 200, 200*(this.height/this.width));
// for browsers supporting the crossOrigin attribute
if (tainted) {
ctx.strokeText('canvas tainted', 20, 100);
ctx.fillText('canvas tainted', 20, 100);
} else {
// for others
try {
canvas.toDataURL();
} catch (e) {
tainted = true;
ctx.strokeText('canvas tainted after try catch', 20, 100);
ctx.fillText('canvas tainted after try catch', 20, 100);
}
}
};
var error_handler = function() {
// remove this onerror listener to avoid an infinite loop
this.onerror = function() {
return false
};
// certainly that the canvas was tainted
tainted = true;
// we need to removeAttribute() since chrome doesn't like the property=undefined way...
this.removeAttribute('crossorigin');
this.src = this.src;
};
img.onload = load_handler;
img.onerror = error_handler;
img.src = urls[0];
btn.onclick = function() {
// reset the flag
tainted = false;
// we need to create a new canvas, or it will keep its marked as tainted flag
// try to comment the 3 next lines and switch multiple times the src to see what I mean
ctx = canvas.cloneNode(true).getContext('2d');
canvas.parentNode.replaceChild(ctx.canvas, canvas);
canvas = ctx.canvas;
// reset the attributes and error handler
img.crossOrigin = 'anonymous';
img.onerror = error_handler;
img.src = urls[+!urls.indexOf(img.src)];
};
但是因为toDataURL
可能只是一个非常重要的检查而且try catch中的代码被去优化,对于旧浏览器来说,更好的选择是创建一个1px*1px测试器画布,首先在其上绘制图像并在try中调用它的toDataURL -catch块:
var urls = ["http://upload.wikimedia.org/wikipedia/commons/4/47/PNG_transparency_demonstration_1.png", "http://lorempixel.com/200/200"];
var img = new Image();
img.crossOrigin = 'anonymous';
var canvas = document.createElement('canvas');
var ctx = canvas.getContext('2d');
document.body.appendChild(canvas);
//create a canvas only for testing if our images will taint our canvas or not;
var taintTester = document.createElement('canvas').getContext('2d');
taintTester.width = 1;
taintTester.height = 1;
var load_handler = function() {
// our image flag
var willTaint = false;
// first draw on the tester
taintTester.drawImage(this, 0, 0);
// since it's only one pixel wide, toDataURL is way faster
try {
taintTester.canvas.toDataURL();
} catch (e) {
// update our flag
willTaint = true;
}
// it will taint the canvas
if (willTaint) {
// reset our tester
taintTester = taintTester.canvas.cloneNode(1).getContext('2d');
// do something
ctx.fillStyle = 'rgba(0,0,0,.7)';
ctx.fillRect(0, 75, ctx.measureText('we won\'t diplay ' + this.src).width + 40, 60);
ctx.fillStyle = 'white';
ctx.font = '15px sans-serif';
ctx.fillText('we won\'t diplay ' + this.src, 20, 100);
ctx.fillText('canvas would have been tainted', 20, 120);
} else {
// all clear
canvas.width = this.width;
canvas.height = this.height;
ctx.fillStyle = 'white';
ctx.font = '15px sans-serif';
ctx.drawImage(this, 0, 0);
}
};
var error_handler = function() {
// remove this onerror listener to avoid an infinite loop
this.onerror = function() {
return false
};
// we need to removeAttribute() since chrome doesn't like the property=undefined way...
this.removeAttribute('crossorigin');
this.src = this.src;
};
img.onload = load_handler;
img.onerror = error_handler;
img.src = urls[0];
btn.onclick = function() {
// reset the attributes and error handler
img.crossOrigin = 'anonymous';
img.onerror = error_handler;
img.src = urls[+!urls.indexOf(img.src)];
};
注意
交叉原始请求不是污染画布的唯一方法:
在IE
因此,在这些情况下检查画布是否被污染的唯一解决方案是try-catch
,并且最好是在1px x 1xx测试画布上执行此操作.
如果crossOrigin
浏览器支持属性/属性(现在它在FF,Chrome,最新的Safari和Edge中),但是服务器没有使用正确的标题(Access-Control-Allow-Origin: *
)回答,那么img的onerror
事件就会触发.
因此,如果我们想要绘制图像,我们可以只处理此事件并删除属性.
对于不处理此属性的浏览器,测试画布是否被污染的唯一方法是调用toDataURL
try catch块.
这是一个例子:
var urls =
["http://upload.wikimedia.org/wikipedia/commons/4/47/PNG_transparency_demonstration_1.png",
"http://lorempixel.com/200/200"];
var tainted = false;
var img = new Image();
img.crossOrigin = 'anonymous';
var canvas = document.createElement('canvas');
var ctx = canvas.getContext('2d');
document.body.appendChild(canvas);
var load_handler = function() {
canvas.width = 200;
canvas.height = 200;
ctx.fillStyle = 'white';
ctx.font = '15px sans-serif';
ctx.drawImage(this, 0, 0, 200, 200*(this.height/this.width));
// for browsers supporting the crossOrigin attribute
if (tainted) {
ctx.strokeText('canvas tainted', 20, 100);
ctx.fillText('canvas tainted', 20, 100);
} else {
// for others
try {
canvas.toDataURL();
} catch (e) {
tainted = true;
ctx.strokeText('canvas tainted after try catch', 20, 100);
ctx.fillText('canvas tainted after try catch', 20, 100);
}
}
};
var error_handler = function() {
// remove this onerror listener to avoid an infinite loop
this.onerror = function() {
return false
};
// certainly that the canvas was tainted
tainted = true;
// we need to removeAttribute() since chrome doesn't like the property=undefined way...
this.removeAttribute('crossorigin');
this.src = this.src;
};
img.onload = load_handler;
img.onerror = error_handler;
img.src = urls[0];
btn.onclick = function() {
// reset the flag
tainted = false;
// we need to create a new canvas, or it will keep its marked as tainted flag
// try to comment the 3 next lines and switch multiple times the src to see what I mean
ctx = canvas.cloneNode(true).getContext('2d');
canvas.parentNode.replaceChild(ctx.canvas, canvas);
canvas = ctx.canvas;
// reset the attributes and error handler
img.crossOrigin = 'anonymous';
img.onerror = error_handler;
img.src = urls[+!urls.indexOf(img.src)];
};