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在经典的asp上传文件

如何解决《在经典的asp上传文件》经验,为你挑选了1个好方法。

我总是使用以下脚本上传经典asp文件,但它停止工作给我这个错误

vbscript运行时错误800a01a8
对象需要'Item(...)'

我调查了一下,我认为问题是在文件upload.asp中使用BuildUploadRequest函数,但我真的不明白为什么

形成
表格登陆的页面
byteCount = Request.TotalBytes
RequestBin = Request.BinaryRead(byteCount)

Dim UploadRequest
Set UploadRequest = CreateObject("Scripting.Dictionary")
BuildUploadRequest(RequestBin)  '//function defined in upload.asp
if UploadRequest.Item("key").Item("Value")="0" then  '//this is the line giving the error
    '//code here...
end if
upload.asp
Sub BuildUploadRequest(RequestBin)
    PosBeg = 1  
    PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(13)))
    boundary = MidB(RequestBin,PosBeg,PosEnd-PosBeg)    
    boundaryPos = InstrB(1,RequestBin,boundary)

    '//Get all data inside the boundaries
    Do until (boundaryPos=InstrB(RequestBin,boundary & getByteString("--")))
        '//Members variable of objects are put in a dictionary object
        Dim UploadControl
        Set UploadControl = CreateObject("Scripting.Dictionary")
        '//Get an object name
        Pos = InstrB(BoundaryPos,RequestBin,getByteString("Content-Disposition"))
        Pos = InstrB(Pos,RequestBin,getByteString("name="))
        PosBeg = Pos+6
        PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(34)))
        Name = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
        PosFile = InstrB(BoundaryPos,RequestBin,getByteString("filename="))
        PosBound = InstrB(PosEnd,RequestBin,boundary)
        '//Test if object is of file type
        If  PosFile<>0 AND (PosFile"
        UploadRequest.Add name, UploadControl   
        '//Loop to next object
        BoundaryPos=InstrB(BoundaryPos+LenB(boundary),RequestBin,boundary)
    Loop
End Sub

'//String to byte string conversion
Function getByteString(StringStr)
  For i = 1 to Len(StringStr)
    charx = Mid(StringStr,i,1)
    getByteString = getByteString & chrB(AscB(charx))
  Next
End Function

'//Byte string to string conversion
Function getString(StringBin)
 getString =""
 For intCount = 1 to LenB(StringBin)
    getString = getString & chr(AscB(MidB(StringBin,intCount,1))) 
 Next
End Function

这段代码在每个项目中都能正常运行,但现在它并不适用于所有项目.所以我不能只编辑和使用其他功能,我需要了解为什么它不再起作用



1> Matt..:

修复#1 - 卸载"KB3104002 IE11的累积安全更新"

修复#2 - 将所有字节数组复制到一个字节值字符串中并对其进行处理,或者提供替代在数组上进行自己迭代的instrb.

Function InstrBNew(startPos, inputArray, searchChar)

  if LenB(searchChar) = 1 Then
    Dim loc
    For loc = startPos to Lenb(inputArray)
      if MidB(inputArray, loc, 1) = searchChar then Exit For
    Next
    InstrBNew = loc
  Else
    InstrBNew = InstrB(startPos, inputArray, searchChar)
  End If
End Function

修复#3 - 微软发布了一个修补程序.这将在2016年1月向所有人发布.您可以在这里尽早得到它.https://support.microsoft.com/en-us/kb/3125446

问题似乎是vbScript中的InstrB函数现在在以下条件下返回值1.

在搜索字节数组时(例如Response.BinaryRead).这在ASP或VBScript中并不常见,但文件上传是您执行此操作时的其中一次.

当您搜索单个字节时

如果您正在搜索字符串,或者您正在搜索多字节模式,那么InstrB正常工作.

PosEnd = InstrB(PosBeg, ByteArray, chrb(13))

在我损坏的系统上,即使在位置1没有字节值13,该函数也总是返回1.在搜索字节数组时,它返回任何值的1.经典的ASP文件上传组件,这就是为什么我们都在这个线程上,遇到这种情况,因为他们正在解析那个字节数组寻找分隔符.

PosEnd = InstrB(PosBeg,ByteArray,getByteString("FormBoundary"))
PosEnd = InstrB(PosBeg,ByteArray,getByteString(vbCRLF))
PosEnd = InstrB(PosBeg,"Normal string", chrb(103)) ' Search for letter g in a string

以上这些行正常工作并且符合预期.多字节搜索和匹配字符串工作预期.

这个问题昨晚在多台服务器上同时出现.我看到昨晚Windows系统更新也在运行.缩小范围,我发现MS15-124(KB3的累积安全更新KB3104002)包含vbscript.dll的更新.我删除了此更新,现在代码恢复正常工作.

我在他们的"IE Con​​nect"系统上提出了一个问题,因为它被包含在IE更新中,但我不确定这是不是正确的地方.

我附上了一个测试用例.在破碎的系统上,它将返回"5,1,5".在工作系统上,它将返回"5,5,5"

希望得到解决方案.一些旧代码在我无法访问的系统上运行.

' Test.vbs
Dim byteArray, byteArray2, byteArray3, bPosition
Dim responseText

' byte string
' "hello hello"
byteArray = chrb(104) & chrb(101) & chrb(108) & chrb(108) & chrb(111) & chrb(32) & chrb(104) & chrb(101) & chrb(108) & chrb(108) & chrb(111) & chrb(0)

' byte array - What Response.BinaryRead is
byteArray2 = TextToBytes(byteArray)

' Vartype: http://stackoverflow.com/questions/3281355/get-the-type-of-a-variable-in-vbscript
ResponseText = ResponseText + "blen: " & lenb(byteArray) & vbCRLF
ResponseText = ResponseText + "type: " & vartype(byteArray) & vbCRLF

ResponseText = ResponseText + "blen: " & lenb(byteArray2) & vbCRLF
ResponseText = ResponseText + "type: " & vartype(byteArray2) & vbCRLF

bPosition = instrb(1, byteArray, chrb(111))
ResponseText = ResponseText + "Position in string: " & bPosition & vbCRLF

bPosition = instrb(1, byteArray2, chrb(111))
ResponseText = ResponseText + "Position in byte array: " & bPosition & vbCRLF

bPosition = instrb(1, byteArray2, chrb(111) & chrb(32))
ResponseText = ResponseText + "Position in byte array: " & bPosition & vbCRLF

WScript.Echo ResponseText

' Converts a string (8) to a vbArray of bytes (8192 + 17)
' I'm not sure how else to create a vbArray of bytes. It does not seem to be a common data type in vbscript
Private Function TextToBytes(ByRef pbinBinaryData)
    Dim lobjRs
    Dim llngLength
    Dim lbinBuffer
    CONST adLongVarBinary = 205
    llngLength = LenB(pbinBinaryData)
    Set lobjRs = CreateObject("ADODB.Recordset")
    Call lobjRs.Fields.Append("BinaryData", adLongVarBinary, llngLength)
    Call lobjRs.Open()
    Call lobjRs.AddNew()
    Call lobjRs.Fields("BinaryData").AppendChunk(pbinBinaryData)
    Call lobjRs.Update()
    lbinBuffer = lobjRs.Fields("BinaryData").GetChunk(llngLength)
    Call lobjRs.Close()
    Set lobjRs = Nothing
    TextToBytes = lbinBuffer
End Function


谢谢!!!!!!!!!!删除了更新,它工作了!这里是如何删除更新http://windows.microsoft.com/en-us/windows/remove-update#1TC=windows-7
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谢谢巷议
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