在C#中格式化具有重要数字的数字

我有一些十进制数据,我将其推入SharePoint列表中进行查看.我想根据我对具体计算的了解来限制结果数据中显示的有效数字的数量.有时候它会是3,所以12345会变成12300而0.012345会变成0.0123.偶尔它会是4或5.有没有方便的方法来处理这个？

请参阅: "P Daddy"的RoundToSignificantFigures.
我把他的方法和我喜欢的另一个方法结合起来.

在TSQL中,舍入到有效数字要容易得多,其中舍入方法基于舍入位置,而不是小数位数 - 这是.Net math.round的情况.您可以将TSQL中的数字舍入到负数位置,这将对整数进行舍入 - 因此不需要缩放.

另见其他帖子.Pyrolistical的方法很好.

问题的尾随零部分对我来说似乎更像是一个字符串操作,因此我包含了一个ToString()扩展方法,如果需要,它将填充零.

using System;
using System.Globalization;

public static class Precision
{
    // 2^-24
    public const float FLOAT_EPSILON = 0.0000000596046448f;

    // 2^-53
    public const double DOUBLE_EPSILON = 0.00000000000000011102230246251565d;

    public static bool AlmostEquals(this double a, double b, double epsilon = DOUBLE_EPSILON)
    {
        // ReSharper disable CompareOfFloatsByEqualityOperator
        if (a == b)
        {
            return true;
        }
        // ReSharper restore CompareOfFloatsByEqualityOperator

        return (System.Math.Abs(a - b) < epsilon);
    }

    public static bool AlmostEquals(this float a, float b, float epsilon = FLOAT_EPSILON)
    {
        // ReSharper disable CompareOfFloatsByEqualityOperator
        if (a == b)
        {
            return true;
        }
        // ReSharper restore CompareOfFloatsByEqualityOperator

        return (System.Math.Abs(a - b) < epsilon);
    }
}

public static class SignificantDigits
{
    public static double Round(this double value, int significantDigits)
    {
        int unneededRoundingPosition;
        return RoundSignificantDigits(value, significantDigits, out unneededRoundingPosition);
    }

    public static string ToString(this double value, int significantDigits)
    {
        // this method will round and then append zeros if needed.
        // i.e. if you round .002 to two significant figures, the resulting number should be .0020.

        var currentInfo = CultureInfo.CurrentCulture.NumberFormat;

        if (double.IsNaN(value))
        {
            return currentInfo.NaNSymbol;
        }

        if (double.IsPositiveInfinity(value))
        {
            return currentInfo.PositiveInfinitySymbol;
        }

        if (double.IsNegativeInfinity(value))
        {
            return currentInfo.NegativeInfinitySymbol;
        }

        int roundingPosition;
        var roundedValue = RoundSignificantDigits(value, significantDigits, out roundingPosition);

        // when rounding causes a cascading round affecting digits of greater significance, 
        // need to re-round to get a correct rounding position afterwards
        // this fixes a bug where rounding 9.96 to 2 figures yeilds 10.0 instead of 10
        RoundSignificantDigits(roundedValue, significantDigits, out roundingPosition);

        if (Math.Abs(roundingPosition) > 9)
        {
            // use exponential notation format
            // ReSharper disable FormatStringProblem
            return string.Format(currentInfo, "{0:E" + (significantDigits - 1) + "}", roundedValue);
            // ReSharper restore FormatStringProblem
        }

        // string.format is only needed with decimal numbers (whole numbers won't need to be padded with zeros to the right.)
        // ReSharper disable FormatStringProblem
        return roundingPosition > 0 ? string.Format(currentInfo, "{0:F" + roundingPosition + "}", roundedValue) : roundedValue.ToString(currentInfo);
        // ReSharper restore FormatStringProblem
    }

    private static double RoundSignificantDigits(double value, int significantDigits, out int roundingPosition)
    {
        // this method will return a rounded double value at a number of signifigant figures.
        // the sigFigures parameter must be between 0 and 15, exclusive.

        roundingPosition = 0;

        if (value.AlmostEquals(0d))
        {
            roundingPosition = significantDigits - 1;
            return 0d;
        }

        if (double.IsNaN(value))
        {
            return double.NaN;
        }

        if (double.IsPositiveInfinity(value))
        {
            return double.PositiveInfinity;
        }

        if (double.IsNegativeInfinity(value))
        {
            return double.NegativeInfinity;
        }

        if (significantDigits < 1 || significantDigits > 15)
        {
            throw new ArgumentOutOfRangeException("significantDigits", value, "The significantDigits argument must be between 1 and 15.");
        }

        // The resulting rounding position will be negative for rounding at whole numbers, and positive for decimal places.
        roundingPosition = significantDigits - 1 - (int)(Math.Floor(Math.Log10(Math.Abs(value))));

        // try to use a rounding position directly, if no scale is needed.
        // this is because the scale mutliplication after the rounding can introduce error, although 
        // this only happens when you're dealing with really tiny numbers, i.e 9.9e-14.
        if (roundingPosition > 0 && roundingPosition < 16)
        {
            return Math.Round(value, roundingPosition, MidpointRounding.AwayFromZero);
        }

        // Shouldn't get here unless we need to scale it.
        // Set the scaling value, for rounding whole numbers or decimals past 15 places
        var scale = Math.Pow(10, Math.Ceiling(Math.Log10(Math.Abs(value))));

        return Math.Round(value / scale, significantDigits, MidpointRounding.AwayFromZero) * scale;
    }
}

这可能会成功:

double Input1 = 1234567;
string Result1 = Convert.ToDouble(String.Format("{0:G3}",Input1)).ToString("R0");

double Input2 = 0.012345;
string Result2 = Convert.ToDouble(String.Format("{0:G3}", Input2)).ToString("R6");

将G3改为G4会产生最奇怪的结果.它似乎围绕有效数字？