我试图使用PHP表单执行mysql查询.以下是表格

        
        
        
        
        
        
        
        

        
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1First Name & Address
        

        
        
        
        
        

        Male
        Female
        
        
        
2Email 
        

        
        
        Validate
        

        
3Passwords
        

        
        
        
        
        
        Agree to Terms and Conditions
        
        
        
        
        
        
        

我在Javascript中有以下表单验证,

function CheckTerms(){
        var letter = /^[a-zA-Z ]*$/;
        if(document.myForm.First_Name.value.match(letter) && document.myForm.First_Name.value =="")
        {
        document.getElementById("error").innerHTML =  "* Please Provide First Name";
        document.myForm.First_Name.focus();
        return false;
        }


        if(document.myForm.Last_Name.value.match(letter) && document.myForm.Last_Name.value =="" )
        {
        document.getElementById("error_l").innerHTML =  "* Please provide your Last name!";
        document.myForm.Last_Name.focus() ;
        return false;
        }


        var email =/^\w+@[a-zA-Z_]+?\.[a-zA-Z]{2,3}$/;
        if(document.myForm.Email_i.value.match(email) && document.myForm.Email_i.value=="")
        {
        document.getElementById("error_e").innerHTML =  "* Please provide your EMAIL!"; 
        document.myForm.Email_i.focus() ;
        return false;
        }


        var min = 6;
        var max = 15;

        if(document.myForm.pass.value.length < min || document.myForm.pass.value.length > max)
        {
        document.getElementById("error_p").innerHTML =  "Password Should be betweeen 6 to 15 characters"; 
        document.myForm.pass.focus() ;
        return false;
        }


        var pass = document.getElementById("Pass").value;
        var re = document.getElementById("RePass").value;

        if(pass != re)
        {
        document.getElementById("error_rp").innerHTML =  "Password do not match";             
        return false;
        }

        if(document.getElementById("check_box").checked == false)
        {
          document.getElementById("error_lable").innerHTML =  "Please Check";
          return false;             
        }}

但问题是,即使javascript返回错误,单击提交按钮,执行PHP脚本导致数据进入数据库.如果存在任何javascript错误,我想停止表单提交.

即使您在函数中执行它,也不会在事件中返回布尔值.默认onSubmit接收true并提交.

更改

onsubmit="CheckTerms()"

至

 onsubmit="return CheckTerms()"