从多维列表Python中获取项目

我有一个具有以下外观的列表:

 [0] = [ [0.0, 100.0], [0.1, 93.08], [0.3, 92.85], [0.5, 92.62], [0.7, 91.12], [0.9, 90.89] ]

 [1] = [ [0.0, 100.0], [0.1, 2.79], [0.3, 2.62], [0.5, 2.21], [0.7, 1.83], [0.9, 1.83] ]

我想获取矢量来绘制信息如下:

[0.0, 0.1, 0.3, 0.5, 0.7, 0.9]
[100.0, 93.08, 92.85, 92.62, 91.12, 90.89]

与列表中的所有条目相同.我在尝试这样的事情:

x = mylist[0][:][0]

有任何想法吗？我很感激帮助!

用途zip:

>>> mylist = [
    [0.0, 100.0], [0.1, 93.08], [0.3, 92.85], [0.5, 92.62],
    [0.7, 91.12], [0.9, 90.89] ]
>>> a, b = zip(*mylist)
>>> a
(0.0, 0.1, 0.3, 0.5, 0.7, 0.9)
>>> b
(100.0, 93.08, 92.85, 92.62, 91.12, 90.89)

>>> list(a)
[0.0, 0.1, 0.3, 0.5, 0.7, 0.9]
>>> list(b)
[100.0, 93.08, 92.85, 92.62, 91.12, 90.89]

使用pure-python,你应该使用list-comprehension

data = [ [0.0, 100.0], [0.1, 93.08], [0.3, 92.85], [0.5, 92.62], [0.7, 91.12], [0.9, 90.89] ]
listx = [item[0] for item in data ]
listy = [item[1] for item in data ]

>>>listx
[0.0, 0.1, 0.3, 0.5, 0.7, 0.9]
>>>listy
[100.0, 93.08, 92.85, 92.62, 91.12, 90.89]

我认为它比zip更好一点,因为它更容易阅读,你不必抛出元组