在互联网上有几个地方向您展示如何获得IP地址.其中很多看起来像这个例子:
String strHostName = string.Empty;
// Getting Ip address of local machine...
// First get the host name of local machine.
strHostName = Dns.GetHostName();
Console.WriteLine("Local Machine's Host Name: " + strHostName);
// Then using host name, get the IP address list..
IPHostEntry ipEntry = Dns.GetHostEntry(strHostName);
IPAddress[] addr = ipEntry.AddressList;
for (int i = 0; i < addr.Length; i++)
{
Console.WriteLine("IP Address {0}: {1} ", i, addr[i].ToString());
}
Console.ReadLine();
在这个例子中,我得到了几个IP地址,但我只对获得路由器分配给运行程序的计算机的一个感兴趣:如果他希望访问我计算机中的共享文件夹,我会给某人的IP实例.
如果我没有连接到网络,我通过没有路由器的调制解调器直接连接到互联网,那么我想得到一个错误.如何查看我的计算机是否通过C#连接到网络,以及是否要获取LAN IP地址.
获取本地IP地址:
public static string GetLocalIPAddress()
{
var host = Dns.GetHostEntry(Dns.GetHostName());
foreach (var ip in host.AddressList)
{
if (ip.AddressFamily == AddressFamily.InterNetwork)
{
return ip.ToString();
}
}
throw new Exception("No network adapters with an IPv4 address in the system!");
}
检查您是否已连接:
System.Net.NetworkInformation.NetworkInterface.GetIsNetworkAvailable();
当本地计算机上有多个IP地址时,有一种更准确的方法.ConnectUDP套接字并读取其本地端点:
string localIP;
using (Socket socket = new Socket(AddressFamily.InterNetwork, SocketType.Dgram, 0))
{
socket.Connect("8.8.8.8", 65530);
IPEndPoint endPoint = socket.LocalEndPoint as IPEndPoint;
localIP = endPoint.Address.ToString();
}
Connect在UDP套接字上具有以下效果:它设置Send/ 的目的地Recv,丢弃来自其他地址的所有数据包,以及 - 我们使用的 - 将套接字转换为"已连接"状态,设置其相应的字段.这包括根据系统的路由表检查到目的地的路由是否存在,并相应地设置本地端点.最后一部分似乎没有正式的文档,但它看起来像是Berkeley套接字API(UDP"连接"状态的副作用)的一个完整特征,它可以在Windows 和Linux中跨版本和发行版可靠地工作.
因此,此方法将提供用于连接到指定远程主机的本地地址.没有建立真正的连接,因此指定的远程IP可以无法访问.
重构Mrcheif的代码以利用Linq(即.Net 3.0+)..
private IPAddress LocalIPAddress()
{
if (!System.Net.NetworkInformation.NetworkInterface.GetIsNetworkAvailable())
{
return null;
}
IPHostEntry host = Dns.GetHostEntry(Dns.GetHostName());
return host
.AddressList
.FirstOrDefault(ip => ip.AddressFamily == AddressFamily.InterNetwork);
}
:)
我知道这可能会踢死马,但也许这可以帮助别人.我已经到处寻找一种方法来查找我的本地IP地址,但我发现它在任何地方都说使用:
Dns.GetHostEntry(Dns.GetHostName());
我根本不喜欢这个,因为它只是获取分配给您的计算机的所有地址.如果您有多个网络接口(几乎所有计算机现在都可以使用这些接口),您不知道哪个地址与哪个网络接口有关.在做了一堆研究后,我创建了一个函数来使用NetworkInterface类并从中提取信息.通过这种方式,我可以分辨出它是什么类型的接口(以太网,无线,环回,隧道等),它是否处于活动状态,以及更多的SOOO.
public string GetLocalIPv4(NetworkInterfaceType _type)
{
string output = "";
foreach (NetworkInterface item in NetworkInterface.GetAllNetworkInterfaces())
{
if (item.NetworkInterfaceType == _type && item.OperationalStatus == OperationalStatus.Up)
{
foreach (UnicastIPAddressInformation ip in item.GetIPProperties().UnicastAddresses)
{
if (ip.Address.AddressFamily == AddressFamily.InterNetwork)
{
output = ip.Address.ToString();
}
}
}
}
return output;
}
现在获取以太网网络接口的IPv4地址调用:
GetLocalIPv4(NetworkInterfaceType.Ethernet);
或者您的无线接口:
GetLocalIPv4(NetworkInterfaceType.Wireless80211);
如果您尝试获取无线接口的IPv4地址,但您的计算机没有安装无线卡,则只会返回一个空字符串.以太网接口也是如此.
希望这有助于某人!:-)
编辑:
有人指出(感谢@NasBanov)即使这个函数以比使用Dns.GetHostEntry(Dns.GetHostName())它更好的方式提取IP地址,但在单个接口上支持相同类型的多个接口或多个IP地址也不是很好.当可能分配多个地址时,它将仅返回单个IP地址.要返回所有这些分配的地址,您可以简单地操作原始函数以始终返回数组而不是单个字符串.例如:
public static string[] GetAllLocalIPv4(NetworkInterfaceType _type)
{
List ipAddrList = new List();
foreach (NetworkInterface item in NetworkInterface.GetAllNetworkInterfaces())
{
if (item.NetworkInterfaceType == _type && item.OperationalStatus == OperationalStatus.Up)
{
foreach (UnicastIPAddressInformation ip in item.GetIPProperties().UnicastAddresses)
{
if (ip.Address.AddressFamily == AddressFamily.InterNetwork)
{
ipAddrList.Add(ip.Address.ToString());
}
}
}
}
return ipAddrList.ToArray();
}
现在,此函数将返回特定接口类型的所有已分配地址.现在只获取一个字符串,您可以使用.FirstOrDefault()扩展名返回数组中的第一个项目,如果它是空的,则返回一个空字符串.
GetLocalIPv4(NetworkInterfaceType.Ethernet).FirstOrDefault();
这是一个修改后的版本(来自compman2408的版本),它对我有用:
internal static string GetLocalIPv4(NetworkInterfaceType _type)
{
string output = "";
foreach (NetworkInterface item in NetworkInterface.GetAllNetworkInterfaces())
{
if (item.NetworkInterfaceType == _type && item.OperationalStatus == OperationalStatus.Up)
{
IPInterfaceProperties adapterProperties = item.GetIPProperties();
if (adapterProperties.GatewayAddresses.FirstOrDefault() != null)
{
foreach (UnicastIPAddressInformation ip in adapterProperties.UnicastAddresses)
{
if (ip.Address.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork)
{
output = ip.Address.ToString();
}
}
}
}
}
return output;
}
更改:我正在从分配了网关IP的适配器中检索IP.
这是我发现获取当前IP的最佳代码,避免获取VMWare主机或其他无效IP地址.
public string GetLocalIpAddress()
{
UnicastIPAddressInformation mostSuitableIp = null;
var networkInterfaces = NetworkInterface.GetAllNetworkInterfaces();
foreach (var network in networkInterfaces)
{
if (network.OperationalStatus != OperationalStatus.Up)
continue;
var properties = network.GetIPProperties();
if (properties.GatewayAddresses.Count == 0)
continue;
foreach (var address in properties.UnicastAddresses)
{
if (address.Address.AddressFamily != AddressFamily.InterNetwork)
continue;
if (IPAddress.IsLoopback(address.Address))
continue;
if (!address.IsDnsEligible)
{
if (mostSuitableIp == null)
mostSuitableIp = address;
continue;
}
// The best IP is the IP got from DHCP server
if (address.PrefixOrigin != PrefixOrigin.Dhcp)
{
if (mostSuitableIp == null || !mostSuitableIp.IsDnsEligible)
mostSuitableIp = address;
continue;
}
return address.Address.ToString();
}
}
return mostSuitableIp != null
? mostSuitableIp.Address.ToString()
: "";
}
我认为使用LinQ更容易:
Dns.GetHostEntry(Dns.GetHostName()) .AddressList .First(x => x.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork) .ToString()
笑了一下，以为我会尝试使用新的C＃6空条件运算符来获得一条LINQ语句。看起来很疯狂，可能效率很低，但是可以用。
private string GetLocalIPv4(NetworkInterfaceType type = NetworkInterfaceType.Ethernet)
{
// Bastardized from: http://stackoverflow.com/a/28621250/2685650.
return NetworkInterface
.GetAllNetworkInterfaces()
.FirstOrDefault(ni =>
ni.NetworkInterfaceType == type
&& ni.OperationalStatus == OperationalStatus.Up
&& ni.GetIPProperties().GatewayAddresses.FirstOrDefault() != null
&& ni.GetIPProperties().UnicastAddresses.FirstOrDefault(ip => ip.Address.AddressFamily == AddressFamily.InterNetwork) != null
)
?.GetIPProperties()
.UnicastAddresses
.FirstOrDefault(ip => ip.Address.AddressFamily == AddressFamily.InterNetwork)
?.Address
?.ToString()
?? string.Empty;
}
逻辑礼貌Gerardo H（并通过引用compman2408）。
@mrcheif I found this answer today and it was very useful although it did return a wrong IP (not due to the code not working) but it gave the wrong internetwork IP when you have such things as Himachi running.
public static string localIPAddress()
{
IPHostEntry host;
string localIP = "";
host = Dns.GetHostEntry(Dns.GetHostName());
foreach (IPAddress ip in host.AddressList)
{
localIP = ip.ToString();
string[] temp = localIP.Split('.');
if (ip.AddressFamily == AddressFamily.InterNetwork && temp[0] == "192")
{
break;
}
else
{
localIP = null;
}
}
return localIP;
}
使用linq表达式获取IP的其他方法：
public static ListGetAllLocalIPv4(NetworkInterfaceType type) { return NetworkInterface.GetAllNetworkInterfaces() .Where(x => x.NetworkInterfaceType == type && x.OperationalStatus == OperationalStatus.Up) .SelectMany(x => x.GetIPProperties().UnicastAddresses) .Where(x => x.Address.AddressFamily == AddressFamily.InterNetwork) .Select(x => x.Address.ToString()) .ToList(); }
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