猫鼬群和伯爵

以下是我的mongodb结构:

[{
    _id: '111',
    items: [{
        productId: '123'
    }]
}, {
    _id: '222',
    items: [{
        productId: '123'
    }, {
        productId: '456'
    }]
}, {
    _id: '333',
    items: [{
        productId: '123'
    }, {
        productId: '456'
    }, {
        productId: '789'
    }]
}]

我期望分组和计数productId,结果是:

[{
    productId: '123',
    count: 3
}, {
    productId: '456',
    count: 2
}, {
    productId: '789',
    count: 1
}]

好吧,我尝试过这样使用aggregation,但我认为我弄错了:

const aggregatorOpts = [{
  $group: {
    _id: "$items.productId",
    count: { $sum: 1 }
  }
}]

Model.aggregate(aggregatorOpts).exec()

我有:

result [
  { _id: [ '123' ], count: 1 },
  { _id: [ '123', '456' ], count: 1 },
  { _id: [ '123', '456', '789' ], count: 1 }
]

关于如何进行聚合的任何帮助可能都很受欢迎,请不要假设模型有任何变化.

提前致谢!

$unwind在分组之前需要items数组:

const aggregatorOpts = [{
        $unwind: "$items"
    },
    {
        $group: {
            _id: "$items.productId",
            count: { $sum: 1 }
        }
    }
]

Model.aggregate(aggregatorOpts).exec()

这使 :

{ "_id" : "789", "count" : 1 }
{ "_id" : "456", "count" : 2 }
{ "_id" : "123", "count" : 3 }