如何使这段代码更具功能性和可读性？

如何使这些javascript语句看起来更具可读性.函数库ramda.js可以用来使这段代码看起来更好吗？

var getTextSpace =  function(len)
    {
            var tlength;
            if (len >= 1 && len <= 4) {
                tlength = 10;
            } else if (len === 5) {
                tlength = 14;
            } else if (len === 6) {
                tlength = 16;
            } else if (len === 7) {
                tlength = 18;
            } else if (len >= 8 && len <= 10) {
                tlength = 20;
            } else if (len === 11) {
                tlength = 22;
            } else if (len === 12) {
                tlength = 24;
            } else if (len >= 13 && len <= 15) {
                tlength = 26;
            } else if (len === 16) {
                tlength = 28;
            } else if (len >= 17 && len <= 20) {
                tlength = 32;
            } else if (len >= 21 && len <= 34) {
                tlength = tlength * 2;
            } else if (len >= 35 && len <= 80) {
                tlength = Math.round((len + len / 100 * 50));
            }
            else {
                tlength = Math.round((len + len / 100 * 30));
            }
        return tlength;
    };

先感谢您.

也许有可能做一些允许这样做的事情？

   value
     .between(2,20).then(20)
     .between(21,22).then(0)
     .greater(25).then(25))
     .less(30).then(function(value) {return value * 20 )})

Scott Sauyet.. 6

拉姆达可能会有所帮助.但主要的是以可读的方式构建范围.下面的代码假定输入值是整数,您不需要测试其他数字类型.那些可以做到,但是你需要比between这里简单更复杂的东西.您需要多个功能或一种方法来配置一个功能,以确定每个开头和结尾是包含还是排他.

var getTextSpace =  (function() {
  // :: (Int, Int) -> (Int -> Bool)
  var between = (begin, end) => R.both(R.gte(R.__, begin), R.lt(R.__, end));
  return R.cond([
    [between(1, 5), R.always(10)],
    [between(5, 6), R.always(14)],
    [between(6, 7), R.always(16)],
    [between(7, 8), R.always(18)],
    [between(8, 11), R.always(20)],
    [between(11, 12), R.always(22)],
    [between(12, 13), R.always(24)],
    [between(13, 16), R.always(26)],
    [between(16, 17), R.always(28)],
    [between(17, 21), R.always(32)],
    [between(21, 35), R.multiply(2)], // assuming original was typo
    [between(35, 80), len => Math.round(len + len / 100 * 50)],
    [R.T, len => Math.round(len + len / 100 * 30)]
  ]);
}());

(原始案例中似乎存在错误:

        } else if (len >= 21 && len <= 34) {
            tlength = tlength * 2;

我认为这意味着什么

        } else if (len >= 21 && len <= 34) {
            tlength = len * 2;

我在这里编写了相应的代码.)

您可以在Ramda REPL上看到这一点.

拉姆达可能会有所帮助.但主要的是以可读的方式构建范围.下面的代码假定输入值是整数,您不需要测试其他数字类型.那些可以做到,但是你需要比between这里简单更复杂的东西.您需要多个功能或一种方法来配置一个功能,以确定每个开头和结尾是包含还是排他.

var getTextSpace =  (function() {
  // :: (Int, Int) -> (Int -> Bool)
  var between = (begin, end) => R.both(R.gte(R.__, begin), R.lt(R.__, end));
  return R.cond([
    [between(1, 5), R.always(10)],
    [between(5, 6), R.always(14)],
    [between(6, 7), R.always(16)],
    [between(7, 8), R.always(18)],
    [between(8, 11), R.always(20)],
    [between(11, 12), R.always(22)],
    [between(12, 13), R.always(24)],
    [between(13, 16), R.always(26)],
    [between(16, 17), R.always(28)],
    [between(17, 21), R.always(32)],
    [between(21, 35), R.multiply(2)], // assuming original was typo
    [between(35, 80), len => Math.round(len + len / 100 * 50)],
    [R.T, len => Math.round(len + len / 100 * 30)]
  ]);
}());

(原始案例中似乎存在错误:

        } else if (len >= 21 && len <= 34) {
            tlength = tlength * 2;

我认为这意味着什么

        } else if (len >= 21 && len <= 34) {
            tlength = len * 2;

我在这里编写了相应的代码.)

您可以在Ramda REPL上看到这一点.