有没有更好的方法将DateTime修剪为特定的精度？

将DateTime对象修剪为特定精度的最佳方法是什么？例如,如果我的DateTime值为'2008-09-29 09:41:43',但我只想要精确到分钟,有没有更好的方法来做到这一点？

private static DateTime TrimDateToMinute(DateTime date)
{
    return new DateTime(
        date.Year, 
        date.Month, 
        date.Day, 
        date.Hour, 
        date.Minute, 
        0);
}

我真正想要的是让它变量,以便我可以将其精度设置为秒,分钟,小时或日.

1> Bartek Szaba..：

---

static class Program
{
    //using extension method:
    static DateTime Trim(this DateTime date, long roundTicks)
    {
        return new DateTime(date.Ticks - date.Ticks % roundTicks, date.Kind);
    }

    //sample usage:
    static void Main(string[] args)
    {
        Console.WriteLine(DateTime.Now);
        Console.WriteLine(DateTime.Now.Trim(TimeSpan.TicksPerDay));
        Console.WriteLine(DateTime.Now.Trim(TimeSpan.TicksPerHour));
        Console.WriteLine(DateTime.Now.Trim(TimeSpan.TicksPerMillisecond));
        Console.WriteLine(DateTime.Now.Trim(TimeSpan.TicksPerMinute));
        Console.WriteLine(DateTime.Now.Trim(TimeSpan.TicksPerSecond));
        Console.ReadLine();
    }

}

---

如果你正在使它成为一个通用的扩展方法,那么值得保留DateTimeKind(Unspecified/Utc/Local):return new DateTime(date.Ticks - date.Ticks%roundTicks,date.Kind);

2> Rikalous..：

---

您可以使用枚举

public enum DateTimePrecision
{
  Hour, Minute, Second
}

public static DateTime TrimDate(DateTime date, DateTimePrecision precision)
{
  switch (precision)
  {
    case DateTimePrecision.Hour:
      return new DateTime(date.Year, date.Month, date.Day, date.Hour, 0, 0);
    case DateTimePrecision.Minute:
      return new DateTime(date.Year, date.Month, date.Day, date.Hour, date.Minute, 0);
    case DateTimePrecision.Second:
      return new DateTime(date.Year, date.Month, date.Day, date.Hour, date.Minute, date.Second);
    default:
      break;
  }
}

并根据需要进行扩展.